Method of shells around a different axis

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SUMMARY

The discussion focuses on using the method of cylindrical shells to calculate the volume generated by rotating the region bounded by the curves y = x² and y = 2 - x² around the line x = 1. The volume formula derived is V = 2π∫ (1-x)(2-2x²)dx, evaluated between -1 and 1, yielding a final volume of 16π/3. The correctness of this method is confirmed, and participants are encouraged to compare it with the disk method to understand the efficiency of each approach.

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  • Understanding of the method of cylindrical shells
  • Knowledge of integral calculus
  • Familiarity with the concept of volume of revolution
  • Ability to evaluate definite integrals
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  • Learn about the application of integration in finding volumes of solids of revolution
  • Study the properties of definite integrals
  • Investigate the comparison of different methods for calculating volumes
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Students studying calculus, particularly those focusing on volume calculations and methods of integration, as well as educators looking for effective teaching strategies in these topics.

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Homework Statement



Use the method of cylindrical shells to find the volume generated by rotation the region bounded by the given curves about the specified axis.

Homework Equations




y = x^2, y = 2-x^2; about x = 1

The Attempt at a Solution



I tried to just break it down.
I want something of the form 2∏rhΔr
OK so To find the height f(x) I subtracted.
2-x^2-x^2 = 2-2x^2. For the radius I did a-x so 1-x is the radius


So I have

V = 2∏∫ (1-x)(2-2x^2)dx between -1 and 1 because that is where the graphs intersect.
Evaluating it I got 2∏((x^4)/2 -(2x^3)/3 -x^2 +2x ] between -1 and 1

I got 16∏/3
Is this the right way?
 
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Yes, it is correct. Try doing it using disks and see if you can obtain the same answer. This will allow you to compare the complexity of the resulting integrals and see why one method is more efficient than the other in this case.
 

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