Michelson Interferometer with a lens

zefanya
Messages
1
Reaction score
0
Homework Statement
This Michelson interferometer is based on a laser with a wavelength of 513 nm. The laser beam first passes though a negative lens with f = -20 mm and then through a positive lens with f = 200 mm. The distance between the lenses is 160 mm. The optical path length from the last lens to the end screen is for the first arm 1200 mm and for the second 1210 mm. How many interference fringes are visible with a radius of 80 mm?
Relevant Equations
2d = mλ
2 d = (m + 1/2)λ
Hello everyone, i have a homework but I'm so confused how to solved it , can someone make a solution manual for this homework?, Thankyou.
 
Physics news on Phys.org
Hello @zefanya ,
:welcome: ##\qquad ## !

with a radius of 80 mm
'with' ? or 'within'? Makes a difference !
zefanya said:
solution manual for this homework
That would only rob you of the exercise, so it is utterly unproductive. Just work your way through:
  • Start with some sketches to clarify the setup
  • Jotting down equations is one thing. Clarify what the symbols stand for and where they fit in the drawing
  • Check if your work and the problem statement agree. Fringes ?
##\ ##
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top