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Micro/macro collection between electrostatic

  1. Jan 27, 2008 #1
    i have question, if A 2.00 mm-diameter copper ball is charged to + 70.0 nC. What fraction of its electrons have been removed?

    I know i have to use the relation, q = (Nprotons - Neletrons)e, but i can't figure out the answer.
    what does e stand for.
    please help
    thankyou
     
  2. jcsd
  3. Jan 27, 2008 #2
    e is the charge of a proton.
     
  4. Jan 27, 2008 #3
    thank
    i still need help for the question though
     
  5. Jan 27, 2008 #4
    It's easy to figure out how many electrons were lost. But if they want to know the fraction of electrons removed, then you'll have to know how much it started with. Using the density of copper and its atomic number and weight from the periodic table, one could figure out how many electrons there would be in a neutral 2mm diameter ball.

    I'm not sure if that's the best way to do this problem though.
     
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