Millikan's oil drop experiment direction

In summary, the conversation discussed the concept of viscous force acting on a charged oil drop in relation to its terminal velocity. The equation for this is Eq = F + U, where F is the viscous force and U is the upthrust force. It was mentioned that viscous force is directly proportional to velocity and only arises when there is movement of the oil drop. The direction of viscous force is always opposite to the direction of motion.
  • #1
logearav
338
0

Homework Statement



Revered members,
Kindly see my attachment.

Homework Equations





The Attempt at a Solution


When the charged oil drop is balanced, electric force = weight of oil drop.
Eq = mg
Eq = F + U, where F is the viscous force and U is the upthrust force. Since the oil drop attains terminal velocity mg = F + U.
I know viscous force always act upwards. But i can't figure out the direction of viscous force when oil drop is balanced. Please help, members
 

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  • #2
If there is no relative movement (between a body and the medium) there will be zero viscous friction force.
 
  • #3
Viscous force is directly proportional to velocity.
Viscous force only arises when there is movement of the oil drop (eg. when the electric field is removed and the drop falls. Here viscous force will continue to increase until upthrust + viscous force = weight. Then, resultant force being zero, the drop will fall with terminal velocity)
Also, viscous force always opposes direction of motion.
 
Last edited:
  • #4
Thanks a lot NascentOxygen and Physics S16 for your replies.
What about the direction of viscous force when terminal velocity is achieved? Will it be upwards?
I think upwards from the statement of Physics S16 that viscous force always opposes direction of motion
 
  • #5
Yes, always exactly opposite to the direction of [relative] motion.
 

1. What is Millikan's oil drop experiment?

Millikan's oil drop experiment was a scientific experiment conducted by physicist Robert A. Millikan in 1909 to measure the charge of an electron. It involved suspending tiny oil droplets in a chamber and measuring their movement in an electric field.

2. What was the significance of Millikan's oil drop experiment?

Millikan's oil drop experiment was significant because it provided the first accurate measurement of the charge of an electron, which was previously unknown. This experiment also confirmed the quantized nature of electric charge and helped to establish the concept of the electron as a fundamental particle.

3. How did Millikan's oil drop experiment work?

Millikan's oil drop experiment involved suspending tiny oil droplets in a chamber between two metal plates. The droplets were then charged by ionizing radiation, and an electric field was applied to the chamber. By adjusting the strength of the electric field, Millikan was able to measure the amount of charge on each droplet and determine the charge of an electron.

4. What were the challenges faced during Millikan's oil drop experiment?

One of the main challenges faced during Millikan's oil drop experiment was the difficulty in accurately measuring the movement of the oil droplets. The droplets were so small and moved so slowly that it was challenging to observe and measure their movements. Additionally, fluctuations in temperature and air currents in the chamber also posed challenges to the accuracy of the experiment.

5. What impact did Millikan's oil drop experiment have on the scientific community?

Millikan's oil drop experiment had a significant impact on the scientific community. It provided the first accurate measurement of the charge of an electron and confirmed the quantized nature of electric charge. This experiment also helped to establish the concept of the electron as a fundamental particle and opened up new avenues for further research in the field of atomic and subatomic particles.

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