Minimize the circuit for this expression

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SUMMARY

The discussion centers on minimizing circuit diagrams derived from a logical expression. Two circuit diagrams were presented, both yielding the same output, but there was confusion regarding the correctness of the first diagram. Participants clarified that the first circuit does not contain an error, and the distinction between the two diagrams lies in the explicit generation of the inverted term b-. Ultimately, both diagrams are valid, with the second diagram showing b- as an available input.

PREREQUISITES
  • Understanding of digital logic design principles
  • Familiarity with circuit minimization techniques
  • Knowledge of Boolean algebra and its applications
  • Experience with circuit diagram representation tools
NEXT STEPS
  • Research circuit minimization methods using Karnaugh maps
  • Learn about the use of inverters in digital circuits
  • Explore tools for simulating digital circuits, such as Logisim
  • Study the principles of Boolean simplification and its impact on circuit design
USEFUL FOR

Electrical engineers, digital circuit designers, and students studying digital logic who seek to enhance their understanding of circuit minimization and diagram representation.

momentum
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Summary: circuit diagram from minimize expression

I am drawing a circuit diagram from a minimize expression. I have come up with two circuit diagrams that give same result.
I am not sure which of the circuit diagram (1) or (2) is correct. Are both my diagram correct? Need help

ZyXRzrn.png
 
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I don't understand this in the first circuit. Is it an error?

1574180061806.png
 
No. This is not error
 
momentum said:
No. This is not error
So inverting b- gives you back b- ?
 
That is not b- . I crossed out that.

Let me post clean image again.. please see this
jjHWM9D.png
 
Well, they are the same then. The only difference is that you explicitly show how you generate b- in the 2nd case. Are you supposed to assume that you have all terms and inversions, or do you need to make your own inverted terms?
 
berkeman said:
The only difference is that you explicitly show how you generate b- in the 2nd case.

did you mean 1st case?
 
momentum said:
did you mean 1st case?
Oops, you are correct. I meant your first case. In the 2nd case, you seem to have b- available to use as an input without having to make it yourself.
 

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