- #1

leejohnson222

- 76

- 6

- Homework Statement
- create a circuit with 2 dc sources of 12v in parallel, one battery has a resistance of 2ohms the second has 4ohms, a lamp is connected between terminal A and B with a 6V rating and 1W

- Relevant Equations
- Thevenin resistance Rth = 1.333ohms

Thevenin Voltage Vth = 12V

so this is a question i am trying to solve and then confirm with the simulation,

so far i have..

Lamp load

IL = PL/VL 1/6 = 0.1667A

Thevenin resistance Rth = Rs1 || Rs 2 = 2 x 4 / 2 +4 = 1.333ohms

Vth = 12V

look at node voltage with load circuit and use kcl

V = 6V

Is1 = 12 -6 / 2 = 3A

Is2 = 12-6/4 = 1.5A

supply can be 4.5A but lamp load is 0.1667A

i think the resistance of the light source is 35.99 ohms ?

i am not sure how i draw this to confirm my working out, i thought i would recreate the circuit and the amp meter would read 4.5A going into the lamp,

so far i have..

Lamp load

IL = PL/VL 1/6 = 0.1667A

Thevenin resistance Rth = Rs1 || Rs 2 = 2 x 4 / 2 +4 = 1.333ohms

Vth = 12V

look at node voltage with load circuit and use kcl

V = 6V

Is1 = 12 -6 / 2 = 3A

Is2 = 12-6/4 = 1.5A

supply can be 4.5A but lamp load is 0.1667A

i think the resistance of the light source is 35.99 ohms ?

i am not sure how i draw this to confirm my working out, i thought i would recreate the circuit and the amp meter would read 4.5A going into the lamp,