MHB Minimizing Cost: Order Size for Optimal Price

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The discussion centers on minimizing the ordering and transportation cost of components in manufacturing, expressed by the equation C=100(200/x^2 + x/(x+30)). Participants calculated the derivative and set it to zero to find the optimal order size, which is approximately 40.45 when using numerical methods like Newton's method. This translates to an order size of 4045 units when considering x in hundreds. The use of graphing utilities, such as the TI-Nspire Cas, confirmed this result. The focus is on finding the order size that minimizes costs effectively.
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Minimum Cost The ordering and transportation cost $C$ of the components used in manufacturing a product is

$C=100\left(\frac{200}{x^2}+\frac{x}{x+30}\right),\ x\ge1$

Where $C$ is measured in thousands of dollars and $x$ is the order size in hundreds.
Find the order size that minimizes the cost. [Hint: use the roots feature of a graphing utility]

I took the derivative of this and set it to zero but did not get the ans of $4045$ units

from the graph it looks like the min would be 40.45 then times 100 would be the ans

thanks ahead
 
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Re: minumum cost

Differentiating and equating to zero results in:

$\displaystyle 3x^3-40x^2-2400x-36000=0$

Using a numeric root-finding technique such as Newton's method yields the real root at:

$\displaystyle x\approx40.45$

Since x represents hundred of units, the answer is then 4045 units.
 
Re: minumum cost

OK on the TI-Nspire Cas it was

zeros$\left(3x^3-40x^2-2400x-36000\right)\approx\ 40.45$
 
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