Minimum Force to Make an Object Move

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SUMMARY

The minimum force required to make a 6 kg object slide on a horizontal surface with a coefficient of friction of 0.8 is calculated using the equation Fsmax = u * Fn. The normal force (Fn) is determined to be 58.8 N, leading to a maximum static friction force (Fsmax) of 47.088 N. To initiate movement, any applied force greater than 47.088 N must be exerted to overcome static friction. The relationship between gravitational force and normal force can be assumed when the object is in static equilibrium.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of static friction and its calculation
  • Familiarity with normal force concepts
  • Basic principles of statics and equilibrium
NEXT STEPS
  • Study the principles of static equilibrium in detail
  • Learn about dynamic friction and its differences from static friction
  • Explore applications of Newton's laws in real-world scenarios
  • Investigate the effects of varying coefficients of friction on motion
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Students studying physics, particularly those focusing on mechanics and statics, as well as educators seeking to clarify concepts of force and friction in introductory courses.

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Homework Statement


A 6 kg object sits on a horizontal surface with coefficient of friction = .8. What is the minimum force (not necessarily horizontal) necessary to make the object slide?

Homework Equations


Fsmax = u * Fn
where Fsmax is the force that must be overcome to make an object move, u is the coefficient of friction, and Fn is the normal force.

The Attempt at a Solution


I was just wondering if this seemed correct:
Fg = -58.8 N (mass * g) so
Fn = 58.8 N
I'm not clear on when exactly one can make the assumption that Fg = Fn
but then using that value of Fn I calculated Fsmax, so the minimum force necessary to make the block move is any force greater than Fsmax.
 
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You need to overcome the force of friction.

The force of friction is
Ff=(coefficient of friction)(weight of object in Newtons)
Ff=(.8)(6*9.81)
Ff=(.8)(58.86)
Ff=47.088N

I think :D
 
uchicago2012 said:
I'm not clear on when exactly one can make the assumption that Fg = Fn

One can always make the assumption that, if the acceleration in some coordinate direction is zero, then by Newton's second law, the sum of all forces acting along that direction must be zero.

This condition for static equilibrium is the foundation for all introductory statics problems.
 

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