Find the force of Friction and minimum coefficient of friction

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SUMMARY

The discussion focuses on calculating the force of friction and the minimum coefficient of friction required for a mass of 50 kg accelerating at 1.0 m/s². The normal force (Fn) is correctly calculated as 450 N. To find the frictional force (Ff), participants are advised to apply the relevant equations, specifically identifying whether the frictional force is static or dynamic based on the context of the problem.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of normal force and friction
  • Knowledge of static and dynamic friction
  • Ability to perform basic algebraic calculations
NEXT STEPS
  • Calculate the frictional force required for horizontal acceleration using Ff = ma
  • Research the differences between static and dynamic friction coefficients
  • Explore the implications of friction in real-world applications, such as vehicle dynamics
  • Study the role of friction in inclined plane problems
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Students in physics, engineers working on mechanical systems, and anyone interested in understanding the principles of friction and motion dynamics.

WhatAnAnomaly
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Homework Statement
A 50.0 kg person is walking horizontally with a constant acceleration of 0.25 m/s2 inside an elevator. The elevator is also accelerating downward at a rate of 1.0 m/s2. Find the force of friction between his shoes and the elevator. What minimum coefficient of friction between his shoes and the floor would make this scenario possible?
Relevant Equations
Fg = mg
Fn = mg-ma
Fnet = ma
Ff = u * Fn
Fg = mg
= 50 * 10
= 500 N

Fn = mg-ma
= 500 - (50.0)(1.0)
= 500-50
= 450

I don't necessarily know if this is right and I can't seem to find the Ff or coefficient of friction either. Please Help!
 
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You're normal force calculation is good. But you should show units on its result.

Now you need to find out what frictional force is required to achieve the stated horizontal acceleration. Knowing that, look to your fourth Relevant Equation. (For additional credit: is the frictional force Static or Dynamic?)
 
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