- #1

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what is the min. stopping distance for the same car traveling at a speed of 38.0 m/s?

tried to use this equation v^2 - u^2 = 2 a s

but then didnt know what to do.

- Thread starter klm
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- #1

- 165

- 0

what is the min. stopping distance for the same car traveling at a speed of 38.0 m/s?

tried to use this equation v^2 - u^2 = 2 a s

but then didnt know what to do.

- #2

Doc Al

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- #3

- 165

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so my a= 10.416

- #4

Doc Al

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- #5

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i used this formula :

0^2 - 38^2 = 2(10.416) x

and found x to be 69.3m but this is incorrect. can you please help me.

- #6

- #7

- 165

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38 x .56?

=21.28 m

but what do i do with that?

=21.28 m

but what do i do with that?

- #8

Doc Al

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The total stopping distance is the sum of both of these distances.

- #9

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you add 21.28 to 60? to get 81.28m?

- #10

- #11

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69.3+21.28 = 90.58?

sorry if i leave really quick i have to run to class in about 2 mins!

- #12

Doc Al

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Yes.

- #13

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THANK YOU!!! so so much

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