Missing gravity and kinetic friction

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SUMMARY

The discussion centers on calculating the work done on a car with a mass of 75,000 kg accelerating from rest to a final velocity of 111.11 m/s in 2.5 seconds. The user correctly applies the work-energy principle, calculating the change in kinetic energy (∆KE) as 463,953,703.8 joules, which equates to the work done (W). The inquiry about missing factors such as gravity and kinetic friction indicates a deeper consideration of real-world physics, although the calculations presented are mathematically sound.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the work-energy theorem
  • Basic knowledge of kinetic energy calculations
  • Concept of forces acting on a vehicle
NEXT STEPS
  • Review the work-energy theorem in classical mechanics
  • Explore the effects of friction on vehicle acceleration
  • Investigate the implications of high mass and velocity on vehicle dynamics
  • Learn about the calculation of forces acting on a moving vehicle
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Physics students, automotive engineers, and anyone interested in the dynamics of vehicle motion and energy calculations.

randomss444
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Homework Statement



What is the network done on the car during the time interval?

Mass = 75,000kg
Vi = 0
vf = 111.11m/s^2
t = 2.5s
∆x = 138.8875m


Homework Equations



W= F∆X

∆KE = (1/2)(m)(v)^2

W = ∆KE

The Attempt at a Solution



∆KE = 1/2(75000kg)(111.11m/s)^2
∆KE = 463953703.8j

And since W=∆KE
W = 463953703.8j

Is this right? I am wondering if I am missing gravity and kinetic friction somewhere?

Thanks
 
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Your method of calculation is correct - I did not plug in the numbers to see if you did that part correctly. I cannot help wondering what kind of car has mass 75,000 kg (75 tons) and is able to go from zero to 111 m/s (250 miles per hour) in 2.5 s.
 

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