1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Mistake on other thread, Here is the problem:

  1. Oct 10, 2006 #1
    Ok sorry about that, here is the actual problem:


    Find the inverse of g(x)

    ok the answer is -x^2+2, but how come the domain is [0,infinity)??
  2. jcsd
  3. Oct 10, 2006 #2
    The range of [tex] g(x) [/tex] is equaled to the domain of [tex] g^{-1}(x) [/tex]. The range of [tex] g(x) [/tex] is [tex] [0, \infty) [/tex]. Thus the domain of [tex] g^{-1}(x) [/tex] is [tex] [0, \infty) [/tex]. Or think of it like this: all the x-values of [tex] g^{-1}(x) [/tex] are really all the y-values of [tex] g(x) [/tex].
  4. Oct 10, 2006 #3
    Oh it all makes sense now, thanks! :smile:
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook