Mixing water with steam, find equilibrim

Click For Summary
SUMMARY

The discussion centers on the thermal equilibrium achieved when mixing 100 g of steam at 100 °C with 500 g of water at 25 °C. The heat lost by the steam during condensation, calculated using the formula Q = mL, is 226,000 J, while the maximum heat the water can absorb, calculated using Q = mcΔT, is 156,975 J. The conclusion is that the steam will condense into water, resulting in a final mixture temperature of 100 °C, as the steam transfers heat until thermal equilibrium is reached. This process is identified as direct contact condensation.

PREREQUISITES
  • Understanding of heat transfer principles
  • Familiarity with the concepts of latent heat and specific heat capacity
  • Knowledge of the equations Q = mL and Q = mcΔT
  • Basic thermodynamics concepts related to phase changes
NEXT STEPS
  • Study the principles of direct contact condensation in thermodynamics
  • Learn about heat exchange calculations in phase change processes
  • Explore the concept of thermal equilibrium in mixtures
  • Investigate the effects of varying mass and temperature in heat transfer scenarios
USEFUL FOR

Students studying thermodynamics, educators teaching heat transfer concepts, and anyone interested in understanding phase changes and thermal equilibrium in physical chemistry.

sallychan
Messages
21
Reaction score
0

Homework Statement


100 g of steam at 100 °C is mixed with 500 g of water at 25 °C. What is the final temperature of the mixture?

Homework Equations



Q= mL

Q= mcΔT

The Attempt at a Solution



Heat given by to water = heat loss at condensation
= mLv
= (0.1) (2.26 E 6)
= 226000 J

Maximum possible heat water can take = mc ΔT
= (0.5) (4186)(100-25)
= 156975 J

Because water does not take up all the latent heat from steam, only some of the steam condensate.

I wonder is my conclusion right? Or will latent heat given by steam actually boils water?

Thanks!
 
Last edited:
Physics news on Phys.org
Your conclusions are correct. Congratulations for having the intuition that 100degC is the maximum temperature possible.
 
But how am I going to find the final temperature if all water is boiled?
 
Think about a 500g pot of water with a tube going to the bottom. Through that tube you inject the 100g steam. What will you see after the water reaches 100C?
 
insightful said:
Think about a 500g pot of water with a tube going to the bottom. Through that tube you inject the 100g steam. What will you see after the water reaches 100C?
Theoretically, when water reaches 100C, they become steam?
 
Picture a bubble of 100C steam entering below the surface of 100C water. What happens to that bubble?
 
insightful said:
Picture a bubble of 100C steam entering below the surface of 100C water. What happens to that bubble?
I think the bubbles will float on the surface of the water... just guessing
 
Good guess! So the bubbles come off the surface carrying the same amount of water that came into the pot with the steam. How much of the water (liquid) phase leaves the pot?
 
insightful said:
Good guess! So the bubbles come off the surface carrying the same amount of water that came into the pot with the steam. How much of the water (liquid) phase leaves the pot?
Oh so you are saying that the steam will condensate? If that is the case, the total amount of water will become 500g + 100g = 600 g.
But how does that happen? Isn't it water does not remove enough latent heat from the steam?
 
  • #10
Well, no. For the steam to condense, the water must be colder than the steam. Think about it for a while.
 
  • #11
insightful said:
Well, no. For the steam to condense, the water must be colder than the steam. Think about it for a while.
Oh right. I understand.
But can you explain a bit more on the heat exchange of condensation? I really want to fully understand it.
Thanks a lot!
 
  • #12
Your problem is called direct contact condensation. As you have realized, the hot steam will condense into the cold water until there is no temperature difference. You have reached equilibrium between the steam and the water at that point. That's really all there is to it.
 
  • #13
insightful said:
Your problem is called direct contact condensation. As you have realized, the hot steam will condense into the cold water until there is no temperature difference. You have reached equilibrium between the steam and the water at that point. That's really all there is to it.
So the steam will always condense when in contact with water in lower temperature?
 
  • #14
You got it.
 
  • #15
insightful said:
You got it.
Okay Thank you very much!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
9
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
4K
  • · Replies 26 ·
Replies
26
Views
34K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K