Model Rocket question regarding height,time,acceleration

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SUMMARY

The discussion revolves around the kinematics of a model rocket that accelerates uniformly to a height of 4.0 m, achieving a speed of 25.0 m/s at that height. The time taken to reach this height is calculated as 0.32 seconds, with an acceleration of 78 m/s². Participants seek assistance in determining the rocket's height and speed at 0.20 seconds after launch, emphasizing the importance of using correct significant figures and understanding the underlying physics concepts. Key equations discussed include h = 1/2 * a * t² for height and V = a * t for speed.

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rsfancy
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A model rocket rises with constant acceleration to a height of 4.0 m, at which point its speed is 25.0 m/s.
How long does it take for the rocket to reach this height? Ans: t= 0.32s
What was the magnitude of the rockets acceleration? Ans a= 78 m/s^2

"Find the height of the rocket 0.20 seconds after launch."
I can't seem to get it right, I know its at least close to 1.5, because that was my original answer but the darned online system says "Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures." the answer is supposed to be to two significant figures.

"Find the speed of the rocket 0.20 seconds after launch."
I haven't attempted this part of the question yet because I think I need to use what I figure out from the previous question to work on this.

All this stuff is not hard, but I can't seem to grasp the simple concepts that I am missing in figuring it out, any help and/or guidance would be really appreciated.
 
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h = 1/2*a*t^2. Put the values of a and t and see how much you get.
 
rsfancy said:
A model rocket rises with constant acceleration to a height of 4.0 m, at which point its speed is 25.0 m/s.
How long does it take for the rocket to reach this height? Ans: t= 0.32s
What was the magnitude of the rockets acceleration? Ans a= 78 m/s^2

"Find the height of the rocket 0.20 seconds after launch."
I can't seem to get it right, I know its at least close to 1.5, because that was my original answer but the darned online system says "Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures." the answer is supposed to be to two significant figures.

"Find the speed of the rocket 0.20 seconds after launch."
I haven't attempted this part of the question yet because I think I need to use what I figure out from the previous question to work on this.

All this stuff is not hard, but I can't seem to grasp the simple concepts that I am missing in figuring it out, any help and/or guidance would be really appreciated.

The thing to keep in mind is what forces (hence accelerations) are acting on the object at different points in time. Since they are asking you for the V and x at a time during which the object was undergoing uniform acceleration starting from rest (V=0) then the equation for finding distance x (or h), is going to be simply
x=1/2 a t2 because the other terms will be 0 because it started at 0 from rest.
Likewise for finding speed you know starting from rest that V = a t

Basically you can use the formulas that relate x, V and t according to what you know and what you need to figure out. Here is a link to various kinematic equations that you might find useful.

https://www.physicsforums.com/showpost.php?p=905663&postcount=2
 

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