Modeling mathematically a rotary flexible beam

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Ben9622111222
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Hi,

I am trying to mathematically model the rotation of a rotary flexible beam. There are numerous papers which study this topic but all of them are considering the beam as a fixed-free one. My case is different.
CAD render of a long slender rotary beam with a square hub mounted near its right end and a gold cylindrical counterweight at the far right, with a thin support wire attached to the hub.

This is the beam I am trying to model. The motor axis is at the square portion towarsd the right end of the beam. The part marked in gold is the counter weight so that motor can be given low current when system is at rest.

I have tested the modes of vibration and found that it shows the nature of a free-free beam upto third mode, but for higher modes it was not clear. Only if I know how the beam behaves, can I go futher with the modeling.
Plot of three curves over a horizontal black line: a red curve and a blue curve, and a green curve with more oscillations, all starting near the same left point.

Also one node was always at the motor axis position.
Can anyone suggest me how I should go forward to understand the beam model and mathematically model it.
Thanks.
 
Mech_Engineer said:
Have you considered doing a modal analysis using a Finite Element Analysis tool like ANSYS or COMSOL?
I have not done a modal analysis. Because the test setup already showed me the nature of vibration upto 12 modes and also the mode frequencies. My ultimate aim is to reduve the free vibration at the tip when it is stopped after a rotation. For this I have developed an equation of motionj. The problem is the terms generalized mass and mode participation factor depend on what boundary condition is selected. And this is dependent on the beam fixation.

So I am confused which boundary condition suits.

The attached figure shows a close approximation. Will this do?
 
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  • Diagram of a horizontal beam pinned at a fixed support near its middle, with a concentrated mass M at the right end, labelled with the note: fixed point, both displacement and slope is zero here, i.e. w=0 and w'=0.
    figure.png
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