Modelling an Exponential Curve

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To model an exponential curve, the equation format a*bt is suggested, with 'a' determined by the initial y-coordinate point. The value of 'b' can be calculated as the growth rate between two points, but using two points to derive 'a' and 'b' through the natural logarithm can simplify the process. For data with noise or imperfect fits, a least squares method is recommended for a more accurate model. Adding a constant to the equation may complicate the model but could be considered if necessary. Overall, using logarithmic transformation and least squares can enhance the precision of the exponential model.
ProPM
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Hi guys,

I need to model a curve and I am trying to come up with an exponential equation. I have several points I can work with and this is what I tried so far. (I want to know if this is the correct method or if there is a more precise way to go about this)

I am working on something of the format: a*bt

My first point in the graph will be when t = 0, hence, I presume the best pick for my value of a would be my first y coordinate point in the graph: 554.8

My doubt arises from this point on:

When I have 554.8*bt should I set up a pair or simultaneous equations or can I say that b is equal to the "rate of growth of my graph"? That is, if my y coordinate points are 609, 657.5 my rate of growth would be (657.5/609)

Since my graph is not a perfect exponential fit I was thinking of adding a constant:

a*bct

But that's something different.

Thanks,
ProPM
 
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I'd probably use y = aebt and use two points to determine a and b. A trick is to take the natural log of both sides so you end up with a linear equation. A more elaborate method (if the points have noise and don't fit a curve perfectly) would be a least squares approach, but that's much more involved (especially in the category of precalculus).
 

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