Solving a Modelling Problem Involving a Sink

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Homework Help Overview

The discussion revolves around a modeling problem involving the dimensions of a sink, specifically focusing on maximizing the cross-sectional area while adhering to constraints related to material size and overlap. The subject area includes geometry and algebraic modeling.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to derive a formula for the cross-sectional area based on the dimensions of the sink and the constraints provided. Some participants question the clarity of the problem and seek further details about the original poster's approach. Others provide alternative equations and calculations to explore the relationship between length and width.

Discussion Status

The discussion is ongoing, with participants offering different interpretations and calculations. Some guidance has been provided regarding the setup of equations, but there is no explicit consensus on the correctness of the original poster's approach or the final outcome.

Contextual Notes

Participants are working within the constraints of a maximum width of 60 cm for the stainless steel sheet and a requirement for a 5 cm overlap on either side of the sink. There is also a mention of needing to clarify the problem statement for better understanding.

Harriet12
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I'm dong a question that involves a sink. The aim is to determine the dimensions of the sink (width and length) which will provide the greated cross-sectional area by modelling using an equation. Here's the catch: you are only allowed a sheet of stainless steel that it 60cm wide and a 5cm overlap has to be allowed for on either side of the sink.

So far I've figured this:
when:
c=cross-sectional ares
a=area
l=length
w=width

a= l x w
c=a
so c= l x w

w=60-(10+2L)

therefore:
c= L[60-(10+2L)]
c=60L-10L+2L^2

etc etc. when applying this formula like this:

L = c/w
L = L[60(10+2L)] / 60(10+2L)

eventually L turns out to be 0 (duh i didnt give it a value)
But here comes my question: is there a flaw in my formula or am i completely off-track? please help!
 
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Harriet,

Perhaps you would clarify exactly what problem you are attempting to solve. I don't understand what you're looking for from what you wrote.
 
lets see what we have

2l + w + 10 = 60

a = l * w

w = 50 - 2l

so a = (50 - 2l) * l

da/dl = 50 - 4l

set = to 0

50 - 4 * l = 0

l = 12.5

plug it in the area equation

50(12.5) - 2(12.5) ^2 = 312.5

you can do the rest yes
 

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