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Molar Mass and density gas relationship

  1. Dec 30, 2008 #1
    1. The problem statement, all variables and given/known data
    The molar mass of carbon dioxide is 0.045kg/mol

    Calculate the density of the gas when thetemperature is 273 K and the pressure is 120 000 Pa

    2. Relevant equations
    Density = mass / volume
    pV = nRT
    n = mass/ molar mass

    3. The attempt at a solution

    I frist want to find n to use in pV = nRT to find V AND to find the mass from n = mass/ molar mass, then I want to use this in the Density = mass / volume to find the density

    I feel im missing an equation? THe one with that abigardo mumbo jumbo in it?

    Thanks :)
  2. jcsd
  3. Dec 30, 2008 #2


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    Try using PV=nRT to find the ratio (n/V), and work from there.

    You cannot find n and V with the given information, you can only find their ratio (n/V). But, you can still find the density.
  4. Dec 30, 2008 #3
    so would the right way be:

    n = mass / molar mass

    n = mass / 0.045

    sub this into pv = nRT

    V = massRT / 0.045p

    sub this into density = mass / volume

    density = mass /[(mass x 8.31 x 273)/(0.045 x 120000)]

    mass cancels... yay

    density = 8.31 x 273 / 45 x 120000

    = 0.42 kg/m³

    is that right?

    Thanks :)
  5. Dec 30, 2008 #4


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    Looks good up to this point.

    You've made an algebraic error. Try putting the units in with the numbers ... you won't get kg/m3 with the answer.
  6. Dec 30, 2008 #5
    density = mass /[(mass x 8.31 x 273)/(0.045 x 120000)]

    so are you saying that bits wrong?

    i thought density would be kg/m³

    density = mass / volume

    mass per volume

    kg per m³

    Can you enlighten me? :)

    Thanks :)
  7. Dec 30, 2008 #6

    [tex]\Rightarrow pV=\frac{m}{M}RT[/tex]

    [tex]\Rightarrow \frac{m}{V}=\frac{pM}{RT}[/tex]

    Do you see your mistake now?

    Like Redbelly said,carry your units. :smile:

  8. Dec 30, 2008 #7
    ahh yes, not both mass mass, one was molecular mass. so all i have to do is work out pM/RT

    = 120000x0.045 / 8.31(273)

    = 2.38

    as for the units


    The SI unit for density is:

    * kilograms per cubic metre (kg/m³)

    and i've go the molecular mass in kg

    I'm stumped :\ Any pointers

    Thanks :)
  9. Dec 30, 2008 #8
    I am not sure what you are asking. What exactly is your question now?
  10. Dec 30, 2008 #9
    are my units for density correct

    Thanks :)
  11. Dec 30, 2008 #10
    Of course they are :smile:

    What Redbelly and I were trying to say was this:

    In post #3 you said density=.42 kg/m3

    That is the reciprocal of the correct answer 2.38 kg/m3 which means that you had it upside-down.

    If you had carried your units during that calculation, you would have gotten m3/kg which would have tipped you off that something was wrong.

    Carrying your units is a good way off checking to see that you answer makes sense.

    Hope that helps :smile:

  12. Dec 30, 2008 #11
    ahh cheers :)
  13. Dec 30, 2008 #12


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    I'm not sure you quite understand what we are telling you to do with the units. Yes, you are aware that density units are kg/m3, but that doesn't mean to simply apply those units to your final calculated number.

    You have to include them as part of the calculation:

    should really be written as

    (120000 Pa)x(0.045 kg/mol) / [(8.31 m3 Pa / (K mol)) (273 K)]

    Many units will cancel out here, leaving you with 2.38 kg/m3. The units come from doing the algebra associated with the calculation, not because we know that's what they should be.

    Had you done that earlier, you would have ended up with

    0.42 m3 / kg

    And, since m3 / kg is not a correct density unit, you would have realized that something had gone awry. That would alert you to check back over your work, and track down the error.

    Working with units this way can often alert you that an error has been made somewhere -- a very useful thing during an exam.

    Hopefully what I wrote is understandable. Good luck! :smile:
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