How Do You Calculate the Final Concentration of a Mixed HCl Solution?

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To calculate the final concentration of a mixed HCl solution, combine the volumes of the two solutions, which total 600 ml. The initial concentrations are 6 M for 200 ml and 1.50 M for 400 ml. Using the formula M1V1 = M2V2, where M1 is the initial concentration and V1 is the initial volume, the equation becomes (6 M)(200 ml) = (M2)(600 ml). Solving this gives a final concentration of 2 M for the mixture. Adding the volumes is valid as they are in the same units.
mugzieee
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200 ml of a 6 M HCl solution is added to 400ml of a
1.50 M HCl solution. find the concentration of the
mixture.

here is what I think should be done:
(6M)(V concentration)=(.8L)(1.50M)

can i add the two volumes together?

Is this correct?
 
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Yeah,the total volume will be 600ml.You have to find the total # of molesof HCl,though...

Daniel.
 


Yes, your approach is correct. To find the concentration of the mixture, you can use the formula M1V1 = M2V2, where M1 and V1 are the initial concentration and volume, and M2 and V2 are the final concentration and volume. In this case, the initial concentration is 6 M and the volume is 200 ml, and the final concentration is what we are trying to find. Therefore, plugging in the values, we get (6 M)(200 ml) = (M2)(600 ml). Solving for M2, we get a final concentration of 2 M for the mixture. And yes, you can simply add the volumes together since they are both in the same units (ml). Great job on solving the problem!
 
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