Molarity of a solution of ethanol in water

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SUMMARY

The molarity of a solution containing ethanol in water, with a mole fraction of ethanol at 0.040, is calculated to be 0.0266 M when assuming a total volume of 150 liters. The mole fraction of water in this solution is 0.96, indicating that the solution consists of 96 moles of water for every 4 moles of ethanol. It is crucial to differentiate between mole fraction and weight/weight percentage, as the latter is 9.6% w/w ethanol, not 4% w/w. This distinction is essential for accurate chemical communication.

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powergirl
Calculate the molarity of a solution of ethanol in water,in which the mole fraction of ethanol is 0.040.
Can anyone help me to solve this problem?:bugeye:
 
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i think

Then the mole fraction of water is 0.96...so the solution is 96% water and 4%Ethanol...this shoule help you going if you were unsure what the fraction was.

Molarity= Moles of Solute / litres of solution

Mole fraction (Ethanol) = Moles of Ethanol/ Moles of Ethanol + Water

So do you know how many Litres or are you just going to assume?

So if we use a basis of 100 moles...96 moles are water and 4 moles are ethanol and assume 150 litres

therefore

molarity = 4 moles /150 litres = 0.0266
 
Thanks for helping me...:)
 
mark-ashleigh said:
Then the mole fraction of water is 0.96...so the solution is 96% water and 4%Ethanol...

Only in terms of moles, stating it this way may sound like you are suggesting this solution is just 4% w/w ethanol - which is not true (it is 9.6% w/w).

It will be better said that such solution contains 4 moles of ethanol per every 96 moles of water.



 
No..i said mole fraction not w/w
 
I know what you mean though...
 

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