Molarity of Sulfuric Acid Solution: 15.206 M

[fish]

Is this how you work this problem:

A sulfuric acid solution has a density of 1.49 g/mL and contains 59 percent H2SO4
by mass. what is the molarity of this solution?

.59x98g = 57.82g H2SO4
1mL/1.49g x 57.82g H2SO4 = .0388L

57.82g H2SO4/ 98g H2SO4 = .59 mol

.59 mol/.0388L = 15.206 M H2SO4

 

[himanshu121]

Now molarity is defined as number of moles of solute per litre of solution.

Now for this wt of solution is= density*Volume =1.49*1000

calculate 59% of this which gives the weight of H2SO4 in solution of 1000mL Divide it by 98 to get the molarity