This one's easy. A 2.9 lb force (P) is applied to a lever. Determine the value of alpha knowing that the moment of P about A is counterclockwise (+) and has a magnitude of 17 lb-in.
Moment about a = (Force of x-component)(distance from a to Force point) + (F_y-comp)(dist. to foce)
M_a = (F_x)(d_y) + (F_y)(d_x)
Answer: alpha = 49.9 degrees or 59.4 degrees
The Attempt at a Solution
17 = (2.9sin(alpha))(4.8) + (2.9cos(alpha))(3.4)
how do I solve for alpha?
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