- #1

cyberdeathreaper

- 46

- 0

Here's the problem:

"The bone rongeur shown [refer to attachment] is used in surgical procedures to cut small bones. Determine the magnitude of the forces exerted on the bone at E when two 25-lb forces are applied as shown."

I understand that this "machine" can be broken into 4 free-body diagrams, and then I can use the equilibrium equations on each one to supposedly find the answer. However, my equations don't readily give me a way to solve for the force at E. Any ideas?

Here's all the equilibrium equations I have come up with:

For the top left piece...

[tex]

\sum F_x = 0 = D_x + B_x

[/tex]

[tex]

\sum F_y = 0 = F_E + D_y - B_y

[/tex]

[tex]

\sum M_D = 0 = -1.2 F_E - 1.6 B_y - 0.45 B_x

[/tex]

For the top right piece...

[tex]

\sum F_x = 0 = -B_x + A_x

[/tex]

[tex]

\sum F_y = 0 = B_y + A_y - 25

[/tex]

[tex]

\sum M_A = 0 = -110 -1.1 B_y + 0.45 B_x

[/tex]

It should be obvious that the bottom pieces are symmetric with the top pieces, and similar in their equilibrium equations.

NOTE: The book indicates the answer is 133.3 lb.

"The bone rongeur shown [refer to attachment] is used in surgical procedures to cut small bones. Determine the magnitude of the forces exerted on the bone at E when two 25-lb forces are applied as shown."

I understand that this "machine" can be broken into 4 free-body diagrams, and then I can use the equilibrium equations on each one to supposedly find the answer. However, my equations don't readily give me a way to solve for the force at E. Any ideas?

Here's all the equilibrium equations I have come up with:

For the top left piece...

[tex]

\sum F_x = 0 = D_x + B_x

[/tex]

[tex]

\sum F_y = 0 = F_E + D_y - B_y

[/tex]

[tex]

\sum M_D = 0 = -1.2 F_E - 1.6 B_y - 0.45 B_x

[/tex]

For the top right piece...

[tex]

\sum F_x = 0 = -B_x + A_x

[/tex]

[tex]

\sum F_y = 0 = B_y + A_y - 25

[/tex]

[tex]

\sum M_A = 0 = -110 -1.1 B_y + 0.45 B_x

[/tex]

It should be obvious that the bottom pieces are symmetric with the top pieces, and similar in their equilibrium equations.

NOTE: The book indicates the answer is 133.3 lb.