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Moment of inertia and rotational kinetic energy

  • Thread starter pb23me
  • Start date
  • #1
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Homework Statement


A merry-go-round has a mass of 1640 kg and a radius of 7.50 m. How much net work is required to accelerate it from rest to a rotation rate of 1.00 revolutions per 8.00s? Assume it is a solid cylinder.


Homework Equations


[itex]\Delta[/itex]KE=Wnet=1/2(Iw2)=14211.7J
[itex]\tau[/itex]=([itex]\Delta[/itex]w/[itex]\Delta[/itex]t)


The Attempt at a Solution

I tryed to get the answer by finding net torque first, but i didnt think i could find the net torque because i dont have the time that the merry go round goes from zero to w=.785rad/s.Then i just used the change in kinetic energy equation to get 14211.7J could i have found this answer the other way???
 

Answers and Replies

  • #2
collinsmark
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[itex]\Delta[/itex]KE=Wnet=1/2(Iw2)=14211.7J
[itex]\tau[/itex]=([itex]\Delta[/itex]w/[itex]\color{red}{\Delta}[/itex]t)
You used the wrong variable! :tongue: It should be Δθ, not Δt

[itex]\tau[/itex] = (ΔW)/(Δθ)​

The Attempt at a Solution

I tryed to get the answer by finding net torque first, but i didnt think i could find the net torque because i dont have the time that the merry go round goes from zero to w=.785rad/s.Then i just used the change in kinetic energy equation to get 14211.7J could i have found this answer the other way???
Yes. You could use kinematics if you wanted to. (But the work-energy theorem, which you ended up using in the end, is much easier.)

If you wanted to use kinematics, use the following equations:
  • W = [itex]\tau[/itex]·θ (definition of work, assuming uniform torque)
  • [itex]\tau[/itex] = (Newton's second law in angular terms)
  • ωf2 - ωi2 = 2αθ (one of your angular kinematics equations).
Combine the equations and solve for W. :smile: (Hint: if you keep everything in terms of variables, and solve for W before substituting in specific numbers, you'll get a pleasing result! :wink:)
 
  • #3
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thank you:smile:
 

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