Moment of inertia by connecting two identical rods

Click For Summary
SUMMARY

The discussion centers on determining the moments of inertia for four T-shaped objects constructed from two identical rods of equal mass and length. Participants utilized the parallel axis theorem and general formulas to reason about the moments without extensive calculations. The consensus indicates that object A has the largest moment of inertia, while object C has the smallest. The moments for objects B and D require further comparison based on their configurations relative to the axis of rotation.

PREREQUISITES
  • Understanding of moment of inertia and its significance in physics.
  • Familiarity with the parallel axis theorem.
  • Basic knowledge of rotational dynamics.
  • Ability to visualize and analyze geometric configurations of rigid bodies.
NEXT STEPS
  • Study the parallel axis theorem in detail to apply it effectively in various scenarios.
  • Learn how to calculate the moment of inertia for different geometric shapes, including rods and T-shaped objects.
  • Explore the implications of mass distribution on rotational motion.
  • Investigate advanced topics in rotational dynamics, such as angular momentum and torque.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding the principles of rotational motion and moment of inertia.

judas_priest
Messages
174
Reaction score
0

Homework Statement


Four T-shaped objects are constructed by connecting two identical rods of equal mass and equal length. Rank in order, from LARGEST to SMALLEST, the moments of inertia for rotation about the axis indicated by the dashed line.


Homework Equations





The Attempt at a Solution



For the first, I used parallel axis theorem for the rod length l away, and for the rod perpendicular to the axis, I took its MI as m*l^2/3. I'm pretty sure that's a wrong approach. I need someone to point out how to go about this.
 

Attachments

  • Untitled.png
    Untitled.png
    2.6 KB · Views: 2,061
Physics news on Phys.org
You do not really need to compute the moments. You can use the general formula and compare them by reasoning whether terms in the formula will be larger or smaller.
 
judas_priest said:

Homework Statement


Four T-shaped objects are constructed by connecting two identical rods of equal mass and equal length. Rank in order, from LARGEST to SMALLEST, the moments of inertia for rotation about the axis indicated by the dashed line.

Homework Equations


The Attempt at a Solution



For the first, I used parallel axis theorem for the rod length l away, and for the rod perpendicular to the axis, I took its MI as m*l^2/3. I'm pretty sure that's a wrong approach. I need someone to point out how to go about this.
Try this. Just look at the pictures. Which do you think has the largest moment of inertia, and which do you think has the smallest? Compare the two intermediate cases. Which do you think has the larger and which do you think has the smaller?

Chet
 
Chestermiller said:
Try this. Just look at the pictures. Which do you think has the largest moment of inertia, and which do you think has the smallest? Compare the two intermediate cases. Which do you think has the larger and which do you think has the smaller?

Chet

A has the largest and C the smallest? Only using intuition and a little physics. Please correct if I'm wrong.
 
voko said:
You do not really need to compute the moments. You can use the general formula and compare them by reasoning whether terms in the formula will be larger or smaller.

In that case A=D. Correct?
 
Cases A and D is similar. The total moment in both case is the sum of the moment of the bar perpendicular to the axis of rotation, and of the moment of the bar parallel to the axis. The moment of the perp. bar is the same in both case; but is the moment of the par. bar the same? Observe its distance from the axis is not equal in the two cases.
 
voko said:
Cases A and D is similar. The total moment in both case is the sum of the moment of the bar perpendicular to the axis of rotation, and of the moment of the bar parallel to the axis. The moment of the perp. bar is the same in both case; but is the moment of the par. bar the same? Observe its distance from the axis is not equal in the two cases.


How do I find the perpendicular Moment of inertia?
 
judas_priest said:
How do I find the perpendicular Moment of inertia?

Well, any moment of inertia is "perpendicular" in the sense that you consider the distance from the axis of rotation, and the distance is perpendicular to the axis.

But what really meant was that there two bars, one in perpendicular and the other parallel to the axis of rotation, and they have certain moment about the axis.
 
voko said:
Well, any moment of inertia is "perpendicular" in the sense that you consider the distance from the axis of rotation, and the distance is perpendicular to the axis.

But what really meant was that there two bars, one in perpendicular and the other parallel to the axis of rotation, and they have certain moment about the axis.

Let me reframe my question -
How do I find the the moment of inertia of the rod perpendicular to the axis asked to find about
 
  • #10
Like I said, you do not really need to find it in this problem. But if you want to anyway, you need to use the general formula for the moment of inertia.
 
  • #11
voko said:
Like I said, you do not really need to find it in this problem. But if you want to anyway, you need to use the general formula for the moment of inertia.

How do I find the moment of inertias in this case? Which is greater than which?
 
  • #12
judas_priest said:
How do I find the moment of inertias in this case? Which is greater than which?

I do not know what "this case" is.

Anyway, what is the definition of the moment of inertia?
 
  • #13
voko said:
I do not know what "this case" is.

Anyway, what is the definition of the moment of inertia?

This case being the question I posted to start the thread. Moment of inertia gives a general idea of the distribution of mass. Given by I = M*R^2
 
  • #14
I have already suggested how you could handle this problem, with more details given in #6. I do not think you hear what I have been saying.
 
  • #15
judas_priest said:
A has the largest and C the smallest? Only using intuition and a little physics. Please correct if I'm wrong.

These are both correct. Now all you need to do is to decide between B and D. Note that the portion of the "T" perpendicular to the axis of B is the same as the portion of the "T" perpendicular to the axis of D. How do the portions of the T's parallel to the axes in this two figures compare in terms of their distances from the axis?
 

Similar threads

Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 28 ·
Replies
28
Views
2K
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
6K
Replies
25
Views
2K