Kindly see the screenshot attached below for the question.
The Attempt at a Solution
In the solution to this question, the moment of inertia of the hands (when outstretched) is taken to be 1/12ML^2 (combined). I think that it should be 1/3ML^2 because the axis is near the shoulder. Also, wouldn't it make any difference if we are calculating the combined moment of the rods rather than calculating individually.
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