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Homework Help: Moment of inertia of a few basic objects

  1. Sep 8, 2012 #1
    Ok i need some help with some homework that is to derive formula for moment of inertia of a few objects about the axis's that i have mentioned
    1. Rectangular slab about axis through center(sides a,b)
    2. Annular cylinder about central axis (radii R1 and R2)

    The only equation i know is Moment of inertia = ∫r[itex]^2[/itex]dm

    any help would be appriciated

    I am new here so if this has been answered pls help me locate and lock this up...

    Thanking in advance....
  2. jcsd
  3. Sep 8, 2012 #2
    Where are you getting stuck? You don't know how to apply the formula you were given? Something else?
  4. Sep 8, 2012 #3
    Hmm i could do it for sphere or ring or others but got struck on slab

    Googled and reached this

    But i could not understand the double integration or how it is done...

    So pls help me solve that if possible...
    Last edited: Sep 8, 2012
  5. Sep 8, 2012 #4
    How did you set up the double integral?
  6. Sep 8, 2012 #5
    What does "axis through center" really mean? There are infinitely many possible axes through the center of a figure.
  7. Sep 8, 2012 #6
    To Muphrid

    Ok What i did is this


    dm=rho*dx*dy (assuming smaller rectangles of length dx and dy)

    di= dI = r2 * rho* da*db

    dI = (r^2 * m * da* db )/ab

    Now it says to integrate with limits from -a/2 to a/2 and -b/2 to b/2

    also couldnt understand what to put in r

    To voko

    Sorry about that
    the axis is passing through center and perpendicular to plane of rectangle
    Last edited: Sep 8, 2012
  8. Sep 8, 2012 #7
    r is the distance from the axis to the (x, y) point.
  9. Sep 8, 2012 #8
    But this distance changes right so what exactly i put??

    Also if possible help me reach a solution
    i mean what would u do to solve??
  10. Sep 8, 2012 #9
    The axis is at the point (0, 0). What is the distance between that point and (x, y)?
  11. Sep 8, 2012 #10
    Don't call them [itex]da, db[/itex]. They're [itex]dx[/itex] and [itex]dy[/itex]. This is what you have:

    [tex]\int_{-b/2}^{b/2} \int_{-a/2}^{a/2} \rho r^2 \; dx \; dy[/tex]

    You're confused about what to put in for [itex]r[/itex]. It should represent the distance to the axis of rotation, but you're integrating in terms of [itex]x,y[/itex]. Is there some way you can put [itex]r[/itex] in terms of [itex]x,y[/itex]?
  12. Sep 8, 2012 #11
  13. Sep 8, 2012 #12
    You are not following the advice given to you. You need to express r in terms of x and y.
  14. Sep 8, 2012 #13
    Thats the thing i cant figure out

    Do u have a solution??
  15. Sep 8, 2012 #14
    Have you heard of the Pythagorean theorem?
  16. Sep 8, 2012 #15
    But the r from the central axis changes all around the rectangle.....
  17. Sep 8, 2012 #16
    Are you saying that you are tasked to compute moments of inertia without studying the basic properties of the Cartesian coordinate system? I fail to see the point of such an assignment.
  18. Sep 8, 2012 #17
    You're not being asked for the distance all around the rectangle, but all throughout the rectangle. Yes, this distance changes as you move within the slab. That's fine. What's important is you have an expression in terms of [itex]x,y[/itex]. Once you do that, you can integrate it.

    You should not expect the distance to be a constant.
  19. Sep 8, 2012 #18
    So which distance do i put in the place of r??
  20. Sep 8, 2012 #19
    What do you mean which distance? Is there more than one you think might be correct?
  21. Sep 8, 2012 #20
    so i put r2=x2+y2

    after that??

    how i solve the double integration??
    Last edited: Sep 8, 2012
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