Moment of inertia of a flywheel

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Homework Help Overview

The problem involves calculating the moment of inertia of a flywheel based on a change in kinetic energy as its angular velocity decreases. The context is rooted in rotational dynamics and energy conservation principles.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conversion of angular velocities from revolutions per minute to radians per second and the implications of kinetic energy changes. There is uncertainty about the correct interpretation of initial and final kinetic energies and how to apply the given change in energy.

Discussion Status

The discussion is active, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the relationship between initial and final kinetic energies, but there remains confusion about the assumptions made in the calculations.

Contextual Notes

Participants are navigating the constraints of the problem statement, particularly regarding the interpretation of kinetic energy values and the assumption that one of them can be zero. The focus is on understanding the implications of the given change in kinetic energy rather than deriving absolute values.

Arejang
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[SOLVED] moment of inertia

Homework Statement


The flywheel of a gasoline engine is required to give up 750 J of kinetic energy while its angular velocity decreases from 870 rev/min to 410 rev/min.

What moment of inertia is required?

Homework Equations



[tex]I=\frac{2K}{\omega^{2}}[/tex]

The Attempt at a Solution



I'm not sure how to derive the rad/sec used in this equation. I've converted both 870 rev/min and 410 rev/min to radians before attempting the problem (91.1 rad/sec and 42.9 rad/sec respectively). I've tried taking the difference between the two, then attempting the average, then just using the final radial velocity and ignoring the initial. I'm not sure what to do at the moment. Can anyone help?
 
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Well they're saying "give up" 750 joules of KE. So you don't actually know any absolute kinetic energies. You know there is a Ki, and that Kf=Ki-750J, you know Ki corresponds with 870rpm and Kf corresponds with 410 rpm, and that is all you're given to work with
 
You started on the right track but got off on the wrong foot.

[tex] \begin{aligned}<br /> K_i &= \frac 1 2 I \omega_i^2 \\[4pt]<br /> K_f &= \frac 1 2 I \omega_f^2 \\<br /> &\Rightarrow \\<br /> K_i-K_f &= \frac 1 2 I (\omega_i^2 - \omega_f^2)<br /> \end{aligned}[/tex]

You can take it from here.
 
I did something, but I'm still not sure I understand it, but it seemed to work.

If I assume [tex]K_{f}[/tex] is 0, then I can set up the problem like so:

[tex]K_{i}=\frac{1}{2}I(\omega_{i}^{2}-\omega_{f}^{2})[/tex]

Solving for I, I get[tex]\frac{2K_{i}}{(\omega_{i}^{2}-\omega_{f}^{2})}=I[/tex]

Plug and chug and got .232 kg*m^2, which is the correct answer.

What I don't understand is why [tex]K_{f}[/tex] is 0.
 
You cannot assume [itex]K_f[/itex] is zero. You are given the change in angular kinetic energy. The problem statement says exactly what [itex]K_i-K_f[/itex] is: 750 joules.
 
So in other words. What K initial and K final are is not important, because the change in kinetic energy is already given in the problem?
 
yeah
 
^_^; man I feel stupid now. Well, anyway thanks!
 

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