Moment of Inertia of Rod About Axis XX': ML2/3sin2α

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SUMMARY

The moment of inertia of a rod about an axis XX' passing through its center of mass at an angle α is expressed as I = ML²/3 sin²α. This formula derives from the standard moment of inertia equation I = ML²/3, with the inclusion of the sin²α term to account for the angle of rotation. The discussion emphasizes the importance of setting up an integral to accurately calculate the moment of inertia when the axis is not aligned with the rod's length. The distance along the axis does not influence the moments about the axis, focusing instead on the perpendicular distances from the axis to the points on the rod.

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Aditya1998
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1. The problem statementα, all variables and given/known data

The moment of inertia of a Rod over an
Axis XX' passing through the center of mass of the Rod at an angle α is-

Homework Equations


Moment of Inertia of Rod about the end, I =ML2/3

The Attempt at a Solution


I=ML2/3
Answer of the question is ML2/3sin2α

I didn't understood how sin2 came because even if we shift OL over the axis XX' then

OX=OLcosα

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Hint: Set up an integral.
 
Aditya1998 said:
I didn't understood how sin2 came because even if we shift OL over the axis XX' then
OX=OLcosα
The distance along the axis, OX, does not affect moments about the axis. The distance of interest is from the XX' axis to the points on the rod.
 

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