Moment of inertia tensor of three spheres

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The discussion focuses on calculating the moment of inertia tensor for a system of three spheres. The user understands the basic moments of inertia (Ixx, Iyy, Izz) but struggles with the off-diagonal components (Ixy, Ixz, Iyz) and their physical meaning. They have derived some values for Ixx and Izz but received feedback questioning their calculations and the omission of contributions from the smaller spheres. The suggestion is made to compute the off-diagonal elements through integration, specifically using the formula Ixy = ∫xy dm. The conversation emphasizes the need for clarity in both the calculations and the understanding of the tensor's structure.
Silken
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Hi everyone

Homework Statement



I want to find out the moment of intertia tensor of the graphic below.



Homework Equations



parallel axis theorem



The Attempt at a Solution



We know the moment of inertia for one sphere, that's given, so I don't have to calculate it explicit.Now I have trouble understanding the moment of inertia tensor. It looks like the following:

I=\begin{pmatrix} I_{xx} & I_{xy} & I_{xz} \\ I_{yx} & I_{yy} & I_{yz} \\ I_{zx} & I_{zy} & I_{zz} \end{pmatrix}

I understand that Ixx, Iyy and Izz are the moments of inertia regarding to x y and z but I don't understand what Ixy Ixz Iyz etc. 'means'. I just can't picture it. Furthermore I tried to find the xx yy and zz, I found out :

I_{xx}=I_{yy}=\frac {54} {5} MR^{2}+9r^{2}m

and

I_{zz}=\frac 4 5 MR^{2}+(R+r)^{2}M

But how do I find the xy xz etc. I know I just have to calculate thre more, because the tensor is symmetrical. But I don't know how do to it. Is my solution right thus far?

Thanks for your help
 

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Silken said:
Hi everyone

Homework Statement



I want to find out the moment of in[STRIKE]t[/STRIKE]ertia tensor of the graphic below.

Homework Equations



parallel axis theorem

The Attempt at a Solution



We know the moment of inertia for one sphere, that's given, so I don't have to calculate it explicitly. Now I have trouble understanding the moment of inertia tensor. It looks like the following:

I=\begin{pmatrix} I_{xx} & I_{xy} & I_{xz} \\ I_{yx} & I_{yy} & I_{yz} \\ I_{zx} & I_{zy} & I_{zz} \end{pmatrix}

I understand that Ixx, Iyy, and Izz are the moments of inertia regarding to x, y, and z, but I don't understand what Ixy, Ixz, Iyz, etc. [STRIKE]'[/STRIKE]mean[STRIKE]s'[/STRIKE]. I just can't picture it. Furthermore I tried to find the xx, yy, and zz, and I found out :

I_{xx}=I_{yy}=\frac {54} {5} MR^{2}+9r^{2}m
I take it M is the mass of the large spheres and m is the mass of the small sphere. How did you get 9mr2? Surely, the contribution of the small sphere must also depend on R. Also, you shouldn't have Ixx=Iyy as far as I can see.
and

I_{zz}=\frac 4 5 MR^{2}+(R+r)^{2}M
What happened to the small sphere? There's no m in your result.
But how do I find the xy, xz, etc. I know I just have to calculate three more, because the tensor is symmetrical. But I don't know how do to it. Is my solution right thus far?

Thanks for your help
Crank out the integrals like
I_{xy} = \int xy\,dm
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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