Moment of inertia tensor of three spheres

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SUMMARY

The discussion focuses on calculating the moment of inertia tensor for a system of three spheres using the parallel axis theorem. The user has successfully derived the diagonal components Ixx, Iyy, and Izz as Ixx = Iyy = (54/5)MR2 + 9r2m and Izz = (4/5)MR2 + (R + r)2M, where M is the mass of the large spheres and m is the mass of the small sphere. However, the user is uncertain about calculating the off-diagonal components Ixy, Ixz, and Iyz, which are essential for a complete tensor representation. The discussion highlights the need for clarity on the physical interpretation of these components and their calculation.

PREREQUISITES
  • Understanding of moment of inertia and its significance in rotational dynamics.
  • Familiarity with the parallel axis theorem and its application in mechanics.
  • Basic knowledge of tensor mathematics, particularly in the context of physics.
  • Ability to perform integrals involving mass distribution in three-dimensional space.
NEXT STEPS
  • Learn how to calculate off-diagonal components of the moment of inertia tensor, specifically Ixy, Ixz, and Iyz.
  • Study the physical significance of the off-diagonal terms in the context of rotational motion.
  • Explore examples of moment of inertia tensor calculations for different geometries, including composite bodies.
  • Review advanced topics in rigid body dynamics, focusing on inertia properties and their implications in engineering applications.
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Students and professionals in physics and engineering, particularly those studying dynamics, mechanics, and material properties related to rotational motion.

Silken
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Hi everyone

Homework Statement



I want to find out the moment of intertia tensor of the graphic below.



Homework Equations



parallel axis theorem



The Attempt at a Solution



We know the moment of inertia for one sphere, that's given, so I don't have to calculate it explicit.Now I have trouble understanding the moment of inertia tensor. It looks like the following:

I=\begin{pmatrix} I_{xx} & I_{xy} & I_{xz} \\ I_{yx} & I_{yy} & I_{yz} \\ I_{zx} & I_{zy} & I_{zz} \end{pmatrix}

I understand that Ixx, Iyy and Izz are the moments of inertia regarding to x y and z but I don't understand what Ixy Ixz Iyz etc. 'means'. I just can't picture it. Furthermore I tried to find the xx yy and zz, I found out :

I_{xx}=I_{yy}=\frac {54} {5} MR^{2}+9r^{2}m

and

I_{zz}=\frac 4 5 MR^{2}+(R+r)^{2}M

But how do I find the xy xz etc. I know I just have to calculate thre more, because the tensor is symmetrical. But I don't know how do to it. Is my solution right thus far?

Thanks for your help
 

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Silken said:
Hi everyone

Homework Statement



I want to find out the moment of in[STRIKE]t[/STRIKE]ertia tensor of the graphic below.

Homework Equations



parallel axis theorem

The Attempt at a Solution



We know the moment of inertia for one sphere, that's given, so I don't have to calculate it explicitly. Now I have trouble understanding the moment of inertia tensor. It looks like the following:

I=\begin{pmatrix} I_{xx} & I_{xy} & I_{xz} \\ I_{yx} & I_{yy} & I_{yz} \\ I_{zx} & I_{zy} & I_{zz} \end{pmatrix}

I understand that Ixx, Iyy, and Izz are the moments of inertia regarding to x, y, and z, but I don't understand what Ixy, Ixz, Iyz, etc. [STRIKE]'[/STRIKE]mean[STRIKE]s'[/STRIKE]. I just can't picture it. Furthermore I tried to find the xx, yy, and zz, and I found out :

I_{xx}=I_{yy}=\frac {54} {5} MR^{2}+9r^{2}m
I take it M is the mass of the large spheres and m is the mass of the small sphere. How did you get 9mr2? Surely, the contribution of the small sphere must also depend on R. Also, you shouldn't have Ixx=Iyy as far as I can see.
and

I_{zz}=\frac 4 5 MR^{2}+(R+r)^{2}M
What happened to the small sphere? There's no m in your result.
But how do I find the xy, xz, etc. I know I just have to calculate three more, because the tensor is symmetrical. But I don't know how do to it. Is my solution right thus far?

Thanks for your help
Crank out the integrals like
I_{xy} = \int xy\,dm
 

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