Moment of Inertia tensor SETUP, not to difficult but cant figure it out

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The discussion focuses on calculating the moment of inertia tensor for a cylinder with mass M, radius R, and height h, specifically about its center of mass. The original poster struggled with setting up the integral in Cartesian coordinates, leading to incorrect results for Ixx. Suggestions were made to switch to cylindrical coordinates, which simplifies the integration process. The correct form for the integral was provided, emphasizing the use of cylindrical coordinates to avoid complications. Ultimately, the poster expressed relief at resolving the issue after the guidance received.
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[SOLVED] Moment of Inertia tensor SETUP, not to difficult but can't figure it out

Homework Statement


a) For a cylinder of mass M, radius R and height h, calculate the inertia tensor about the center of mass. What are the principal axes?

Homework Equations



mimg273.gif


The Attempt at a Solution


I need help with setting up the integral. I placed the origin at the center of the cylinder. So and i set my boundaries as = z going from -h/2 to h/2, y going from -R to R and x going from -sqrt(R^2-y^2) to sqrt(R^2-y^2).

However when i integrate Ixx I get zero and I know I am not suppose to. Is there a better choice for my boundaries?? My x boundaries are the problem here because they give me a ugly answer.

Thanks
 

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Try to use cylindrical coordinates, this will simplify the problem.
 
so for Ixx will the integral be
r^2sin^2(theta) + h^2 r^2sin(theta)dr d(theta) dz??

thank you
 
Last edited:
Not shperical coordinates, cylindrical ones! :smile:

x=r\,\cos\phi,\,y=r\,\sin\phi \Rightarrow d\,x\,d\,y\,d\,z=r\,d\,r\,d\,\phi\,d\,z

thus I_{xx} reads

I_{xx}=\int_V \rho(r,\phi,z)\,\left(r^2\,\sin^2\phi+z^2\right)\,r\,d\,r\,d\,\phi\,d\,z
 
Last edited:
got it! I feel so dumb spending so much time trying to figure it out in cartesian coord. Thank you so much!
 

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