Moment of Inertia tensor SETUP, not to difficult but cant figure it out

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Homework Help Overview

The discussion revolves around calculating the moment of inertia tensor for a cylinder with given mass, radius, and height, specifically focusing on the setup of the integral required for the calculation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to set up the integral in Cartesian coordinates but encounters issues with the boundaries leading to an unexpected result for Ixx. Some participants suggest using cylindrical coordinates to simplify the problem, while others provide specific integral formulations.

Discussion Status

Participants are actively exploring different coordinate systems and integral setups. Guidance has been offered regarding the use of cylindrical coordinates, which appears to be a productive direction for the discussion.

Contextual Notes

The original poster expresses frustration with the Cartesian coordinate approach and is seeking clarification on the boundaries for integration. There is an indication of confusion regarding the setup that may be affecting the results.

m0nk3y
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[SOLVED] Moment of Inertia tensor SETUP, not to difficult but can't figure it out

Homework Statement


a) For a cylinder of mass M, radius R and height h, calculate the inertia tensor about the center of mass. What are the principal axes?

Homework Equations



mimg273.gif


The Attempt at a Solution


I need help with setting up the integral. I placed the origin at the center of the cylinder. So and i set my boundaries as = z going from -h/2 to h/2, y going from -R to R and x going from -sqrt(R^2-y^2) to sqrt(R^2-y^2).

However when i integrate Ixx I get zero and I know I am not suppose to. Is there a better choice for my boundaries?? My x boundaries are the problem here because they give me a ugly answer.

Thanks
 

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Try to use cylindrical coordinates, this will simplify the problem.
 
so for Ixx will the integral be
r^2sin^2(theta) + h^2 r^2sin(theta)dr d(theta) dz??

thank you
 
Last edited:
Not shperical coordinates, cylindrical ones! :smile:

[tex]x=r\,\cos\phi,\,y=r\,\sin\phi \Rightarrow d\,x\,d\,y\,d\,z=r\,d\,r\,d\,\phi\,d\,z[/tex]

thus [itex]I_{xx}[/itex] reads

[tex]I_{xx}=\int_V \rho(r,\phi,z)\,\left(r^2\,\sin^2\phi+z^2\right)\,r\,d\,r\,d\,\phi\,d\,z[/tex]
 
Last edited:
got it! I feel so dumb spending so much time trying to figure it out in cartesian coord. Thank you so much!
 

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