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Moments about two points of an object
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[QUOTE="shott92, post: 4730837, member: 509239"] thanks very much 1) i thought that Fc should be acting on Cg but the results did not equate as i later stated, 2) although not drawn on yes i am aware that there should be an equal friction force at the contact patch opposing Fc 3) I am going to sound dense here but, normal force, what do you mean the they are Mg, Fc and Fsr are they not?? 4)i was planning on taking into account deformation of the tyre but since I am struggling already and my deadline approches i going to dismiss that. 5) and although it sounds silly yes i am ignoring gyroscopic affect although if the mass of the wheel or (MoI) is (in your opinon) a significant part to the solution despite gyroscopic effect then i don't think it would be to hard to consider it because i assumed that as allowing the force to act on CG did not give the answers i was looking for in my desperation i was looking for any other feesable method of find the results (needless to say it also gave an incorrect answer) could you elaborate on why the relative magnetudes would allow the torque to be anything other than 0 if it is running through the cog B and A (this is why i considered the deformation of the tyre however it proved extremely hard to calculate accuratly and using approximations did not give the expected results either) and yes for the whole thing i am assuming the bike being in equilibrium i have all the prior equations to calculate Fc ect. i am not looking for a worked answer but the generic equation or formula the rest i can calculate for myself if it helps for your responce purposes the one a under the same cornering conditions Fc = 701.98 Fsr = 1819.45 and MG = 2609.45 and just if it is relavant the traction co efficient (mu) is 1.1 i really hope this helps you help me, and i would like to thank you so much for your time it really is appreciated [/QUOTE]
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Moments about two points of an object
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