Momentum Concervation and Collisions

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SUMMARY

The discussion revolves around two physics problems involving momentum conservation and collisions. The first problem involves a bullet of mass 7.00 g traveling at 400 m/s colliding with a wooden block of mass 0.850 kg, which slides 48.0 m after the bullet passes through it. The coefficient of kinetic friction and the block's kinetic energy post-collision are to be determined. The second problem involves a blue puck of mass 0.038 kg colliding elastically with a red puck at rest, requiring the calculation of the red puck's velocity and mass. Key equations used include the conservation of momentum and kinetic energy formulas.

PREREQUISITES
  • Understanding of linear momentum conservation principles
  • Familiarity with kinetic energy calculations
  • Knowledge of elastic and inelastic collisions
  • Basic grasp of friction and its coefficient
NEXT STEPS
  • Study the conservation of momentum in elastic and inelastic collisions
  • Learn how to calculate the coefficient of kinetic friction using distance and forces
  • Explore detailed examples of kinetic energy calculations in collision scenarios
  • Investigate the differences between elastic and inelastic collisions with practical examples
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Students studying physics, particularly those focusing on mechanics, collision theory, and momentum conservation. This discussion is beneficial for anyone tackling similar homework problems or preparing for exams in introductory physics courses.

mr.quakers
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Homework Statement




A bullet with a mass of 7.00 , traveling horizontally with a speed of 400 , is fired into a wooden block with mass of 0.850 , initially at rest on a level surface. The bullet passes through the block and emerges with its speed reduced to 200 . The block slides a distance of 48.0 along the surface from its initial position.

What is the coefficient of kinetic friction between block and surface?

What is the kinetic energy of the block at the instant after the bullet passes through it?

Homework Equations



P=m1v1 + m2v2

KE = 1/2mv^2

...I think, I'm not completely sure on if it is elastic or inelastic. Our physics book is honestly terrible and has no examples relating to this.


The Attempt at a Solution



I really have no idea where to start. I've tried setting the momentums equal to each other and solving for v, but that doesn't work.

Second question:

A blue puck with a mass of 3.80×10−2 , sliding with a speed of 0.200 on a frictionless, horizontal air table, makes a perfectly elastic, head-on collision with a red puck with mass , initially at rest. After the collision, the velocity of the blue puck is 2.0×10−2 in the same direction as its initial velocity.

Find the magnitude of the velocity of the red puck after the collision.

Find the mass of the red puck.

Once again, no idea where to start.
 
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mr.quakers said:

Homework Statement




A bullet with a mass of 7.00g , traveling horizontally with a speed of 400 ms^-1 , is fired into a wooden block with mass of 0.850kg , initially at rest on a level surface. The bullet passes through the block and emerges with its speed reduced to 200 . The block slides a distance of 48.0m along the surface from its initial position.

What is the coefficient of kinetic friction between block and surface?

What is the kinetic energy of the block at the instant after the bullet passes through it?
The letters in bold are what I assumed to be units.
Before collision:
Block has mass 0.850kg with a velocity of 0ms^-1
Bullet has mass 7g with a velocity of 400ms^-1

After collision:
Block moves with a velocity of Vms^-1
Bullet moves with velocity of 200ms^-1

Using the law of conservation of linear momentum
\frac{7}{1000}\times 400 + 0.850\times 0 = 0.850V+\frac{7}{1000}\times 200

Is that what you did and it didn't work out?

Also an elastic collision is one in which kinetic energy is conserved.
 
No that doesn't work. I have one more question, this section seems to be particularly bad at explaining the concepts.

A 22.00 lead sphere is hanging from a hook by a thin wire 3.80 long, and is free to swing in a complete circle. Suddenly it is struck horizontally by a 5.00 steel dart that embeds itself in the lead sphere.
 
mr.quakers said:
No that doesn't work.

The velocity of the block is not obtained in that way? Well I don't see any other way to get it.


mr.quakers said:
A 22.00 lead sphere is hanging from a hook by a thin wire 3.80 long, and is free to swing in a complete circle. Suddenly it is struck horizontally by a 5.00 steel dart that embeds itself in the lead sphere

What exactly are you supposed to do in this one?
 
I though I edited in the question, sorry. It's too late now though, the assignment is due in 15 minutes. Thanks for your help.
 

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