Momentum Conservation: Bullet enters a block

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SUMMARY

The discussion centers on the application of conservation of momentum in a scenario where a bullet enters a block. Participants clarify the need for specific variables, particularly the height (h) and the angle (a), to solve for the velocity (V) of the block. The equation derived from Pythagoras' theorem, \( l^2 = (l-h)^2 + a^2 \), is emphasized as essential for understanding the relationship between these variables. The conversation concludes with a participant expressing clarity after receiving assistance.

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  • Understanding of conservation of momentum principles
  • Familiarity with Pythagorean theorem applications
  • Basic knowledge of kinematics and projectile motion
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the principles of conservation of momentum in collisions
  • Learn how to apply Pythagorean theorem in physics problems
  • Explore kinematic equations related to projectile motion
  • Investigate the effects of angle and height on projectile trajectories
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Physics students, educators, and anyone interested in understanding momentum conservation and its applications in collision scenarios.

Shreya
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Homework Statement
I am not able to solve the second part of the question.
Please refer the image below.
V refers to the final velocity after collision, v is the initial velocity of bullet. L is the length of string and h is the height that the block rises to.
Relevant Equations
Conservation of Momentum
I can understand that using conservation of momentum, we can find v. But we need V for that. The equation for V involves h and so we need h. But I am not able to comprehend the equation involving l,h and a. The question doesn't specify what a is.
Please be kind to help
 

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That’s just Pythagoras’ theorem.
$$
l^2 = (l-h)^2 + a^2
$$
Expand the (l-h) square and cancel ##l^2## on both sides.
 
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Orodruin said:
That’s just Pythagoras’ theorem.
Thanks @Orodruin! I get it now.
 
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