Momentum Conservation in Ideal Gas & Piston Collision

qazxsw11111
Messages
95
Reaction score
0

Homework Statement


The cylinder and piston are made of a thermal insulator. An atom of a gas collides with the piston at an angle and bounces off at an angle. State with a reason whether momentum of the atom is conserved in this collision.


Homework Equations





The Attempt at a Solution


I think that momentum of atom is not conserved as it is a vector quantity and hence change in momentum when there is a change in direction of the atom velocity.

However, the answer says that it is how you consider what is the "system". If atom is the "system", momentum is changed. If "piston+cylinder+atom"=system, momentum is conserved.

Im really confused! Which one is right?
 
Hi qazxsw11111,

qazxsw11111 said:

Homework Statement


The cylinder and piston are made of a thermal insulator. An atom of a gas collides with the piston at an angle and bounces off at an angle. State with a reason whether momentum of the atom is conserved in this collision.


Homework Equations





The Attempt at a Solution


I think that momentum of atom is not conserved as it is a vector quantity and hence change in momentum when there is a change in direction of the atom velocity.

However, the answer says that it is how you consider what is the "system". If atom is the "system", momentum is changed. If "piston+cylinder+atom"=system, momentum is conserved.

Im really confused! Which one is right?

I'm not sure what you are asking here; you have the same answer as the answer key. The momentum of the atom changes.

If you are examining just the atom by itself (which is what is meant by defining the system to be the atom), then during the collision there is a large external impulse on the system--from the piston. With a large external impulse, the momentum changes (is not conserved).

If your system is (piston+cylinder+atom), then there is no external impulse due to the collision, because the collision forces are between system objects (and so action-reaction forces will have cancelling impulses). So for that system momentum is conserved.

Remember that the test for conservation of momentum is the impulse momentum relationship, which for average forces is:

[tex] \vec F_{\rm ext}\Delta t=\Delta \vec p[/tex]

(and there is also the integral form if your problem requires it).
 

Similar threads

Replies
8
Views
3K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
17
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
12K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K