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Momentum Flux: Quick Question (Product Rule)

  1. Dec 2, 2009 #1
    1. The problem statement, all variables and given/known data
    Heya,
    I can expand the term on the LHs and get the term on the RHS no problem :)
    But,
    I don't understand how the bottom line is arrived at; I think its basically just a backward engineering of the product rule, but I can't get it!

    Any help would be useful
     

    Attached Files:

  2. jcsd
  3. Dec 2, 2009 #2
    [tex] \frac{\partial(\rho u u)}{\partial x} = \rho u \frac{\partial u}{\partial x} + u \frac{\partial (\rho u)}{\partial x}. [/tex]
     
  4. Dec 2, 2009 #3
    Thanks
    :surprised That was easier than I thought!
     
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