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## Homework Statement

A battle ship (4.09*10^7 kg) fires a salvo of 3 rounds from its foward turret in the direction of the bow at an angle of 10 degrees above the horizontal. Each projectile weighs 1220 kg, each barrel is 20.9 m long and the muzzle velocity of the projectile is 770 m/sec. Acceleration of each projectile down the barrel is 1.418 x 10^4 m/s2 at 0.0543 seconds.

If the momentum must be conserved in the x direction,

**1) what's the velocity of the ship in the x direction**and

**2) in what direction is it moving along the x axis after the projectiles have left the ship's guns?**

## Homework Equations

**p**(linear momentum of an object)=

**mv**

M1V1 + M2V2=0

## The Attempt at a Solution

1) I'm not sure whether I should get the velocity of the projectile in the x direction, but I just used it's velocity in the x direction in solving the problem. I did the trigonometric work on paper.

M1V1 + M2V2=0

V2= -M1/M2(V1)

V2= -1220/4.09*10^7(758.3)

V2= -.0226 m/sec

2) The ship recoils to the left of the x axis.

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