- #1

canvas01

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My approach: Because the asteroid is not rotating, it has no angular momentum, just linear momentum represented as mv. The Earth however, has no linear momentum, just angular momentum which is equal to Iw where I = .4mr^2 and w = v/r where v = circumference of the earth/time of one complete rotation of the earth. I'm confused as to where to go from here? How are the angular momentum of the Earth and the linear momentum of the asteroid related?