Momentum of System Homework: Total Momentum at h/2

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The discussion centers on calculating the total momentum of a system consisting of a ball of mass m and the Earth, where the ball falls a distance of h/2. The correct answer for the total momentum of the system is determined to be C: Me(sqrt(2gh)). The user Kevin initially guessed B but later considered C, indicating a misunderstanding of the momentum contributions from both the ball and the Earth. The relevant equation for momentum, p = mv, is applied to both the ball and the Earth to derive the total momentum.

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Homework Statement


A system initially consists of a ball of mass m at rest at a height h above the Earth and the Earth, of mass Me. When the ball has fallen a distance h/2, the total momentum of
the system is
A. 0
B. m(sqrrt)2gh
C. Me(sqrrt)2gh
D. Me + m(sqrrt)2gh
E. Me - m(sqrrt)2gh


Homework Equations





The Attempt at a Solution


I put B and missed it. I think the answer is C but not sure.
Any help understanding this would be appreciated.
Thanks,
Kevin
 
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Husker70 said:

Homework Statement


A system initially consists of a ball of mass m at rest at a height h above the Earth and the Earth, of mass Me. When the ball has fallen a distance h/2, the total momentum of
the system is
A. 0
B. m(sqrrt)2gh
C. Me(sqrrt)2gh
D. Me + m(sqrrt)2gh
E. Me - m(sqrrt)2gh


Homework Equations





The Attempt at a Solution


I put B and missed it. I think the answer is C but not sure.
Any help understanding this would be appreciated.
Thanks,
Kevin


[tex]\textbf{v}_f^2=\textbf{v}_i^2+2\textbf{ad}[/tex]

so, [tex]\textbf{v}=\sqrt{2\textbf{ad}}[/tex], and:

[tex]\textbf{p}=m\textbf{v}=m\sqrt{2\textbf{ad}}[/tex].

The total momentum of the system is the sum of momenta of the particles. The above momentum is that of the ball. The momentum of the Earth is given by:

[tex]M_e\textbf{v_e}=[/tex],

add them and that's your answer which isn't readily available, sadly. Maybe someone else has more of an intuitive approach.
 

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