What Happens to Two Blocks After an Elastic Collision on a Slope?

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SUMMARY

The discussion focuses on an elastic collision problem involving two blocks, where a 2.80 kg block slides down a 30.0° incline and collides with a stationary 7.00 kg block. To solve for the speeds of both blocks after the collision, one must first calculate the initial velocity of the lighter block using energy conservation principles. The relevant equations include momentum conservation and kinematic equations. The final velocities can then be determined, followed by calculating how far the lighter block travels back up the incline after the collision.

PREREQUISITES
  • Understanding of elastic collisions and momentum conservation
  • Knowledge of energy conservation principles in physics
  • Familiarity with kinematic equations, specifically v^2 = u^2 + 2as
  • Basic trigonometry to resolve forces on an incline
NEXT STEPS
  • Learn how to apply energy conservation to determine initial velocities in collision problems
  • Study momentum conservation in elastic collisions, particularly with two bodies
  • Explore kinematic equations in the context of motion on an incline
  • Investigate the effects of friction and incline angles on collision outcomes
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for practical examples of elastic collisions in a classroom setting.

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Homework Statement


A block of mass m = 2.80 kg slides down a 30.0° incline which is 3.60 m high. At the bottom, it strikes a block of mass M = 7.00 kg which is at rest on a horizontal surface, Fig. 7-41. (Assume a smooth transition at the bottom of the incline, an elastic collision, and ignore friction.)
http://img141.imageshack.us/img141/4472/741ue2.gif


(a) Determine the speeds of the two blocks after the collision.
Lighter Block:
Heavier Block:

(b) Determine how far back up the incline the smaller mass will go.


Homework Equations



v=final velocity
u= Initial velocity
a=acceleration
s= Displacement
v^2=u^2+2as

m1u1+m2u2=m1v1+m2v2

The Attempt at a Solution



I resolved to find acceleration perpendicular to the plain of motion and also the displacement, but as i was not given an initial velocity i cannot find out the final velocity of the small block as it hits the large block

Does anyone have any ideas as to how i would go about solving this question?
 
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i think you have to assume that the block starts at rest here.

to start, use energy conservation methods to find the velocity of the small block at the bottom of the incline.
 

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