Momentum question -- A boy drops a box while sliding on ice....

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Homework Help Overview

The problem involves a boy sliding on ice while holding a box and dropping it, with a focus on calculating the momentum of the boy immediately after the drop. The scenario includes considerations of mass, velocity, and the effects of negligible friction.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of conservation of momentum and question the velocity of the box after it is dropped. There are attempts to clarify whether the box retains its horizontal velocity after being released.

Discussion Status

The discussion is ongoing, with various interpretations being explored regarding the box's velocity post-drop and its implications for the boy's momentum. Some participants are questioning assumptions about forces acting on the box and the relevance of those forces to the boy's momentum.

Contextual Notes

There is a lack of explicit information regarding any forces acting on the box after it is dropped, leading to differing opinions on its velocity. The original poster's statement does not provide details on horizontal forces, which has prompted further inquiry into the problem's setup.

kellyxx
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Homework Statement


A boy is holding a box and moving at a constant velocity of 2m/s on ice. The masses of the boy and the box are 40kg and 2kg respectively.Then the boy drops the box. What is the momentum of the boy just after dropping the box? Assume that the friction between the boy and the ice is negligible.
2. The attempt at a solution
I've tried to apply the conservation of momentum (m1u1+m2u2=m1v1+m2v2)
(40+2)(2)=2(0)+40v then v=84 kgms-1, but the correct answer should be 80kgms-1
 
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kellyxx said:
What is the momentum of the boy just after dropping the box? Assume that the friction between the boy and the ice is negligible.
after dropping the box -what is the velocity of the boy and the box ?
 
Notice what the question is asking for:

kellyxx said:
What is the momentum of the boy just after dropping the box?

What did you find the momentum to in your work?
 
drvrm said:
after dropping the box -what is the velocity of the boy and the box ?
The question didn't mention about that, but from my understanding, the velocity of the box after the drop should be 0ms-1
 
kellyxx said:
The question didn't mention about that, but from my understanding, the velocity of the box after the drop should be 0ms-1

The velocity of the box before being dropped was 2 m/s. After being dropped, was there any acceleration in the horizontal direction to change its velocity?
 
Drakkith said:
The velocity of the box before being dropped was 2 m/s. After being dropped, was there any acceleration in the horizontal direction to change its velocity?
hmmm I guess there isn't any.
 
Drakkith said:
The velocity of the box before being dropped was 2 m/s. After being dropped, was there any acceleration in the horizontal direction to change its velocity?
Just to be accurate about this, what happens after letting go the box is irrelevant to the boy's momentum. The question that needs asking is what horizontal force, if any, caused the box to go from 2m/s to 0m/s as the boy released it.
 
Madame, I don't really think that velocity of the box is zero. Imagine that you are holding a lipstick, you go through a hole but you accidentally drop your favorite lipstick. Thanks to physics, it has your velocity instead of zero. Your lipstick survives ! If you release an object while you are having velocity, that object will have the same velocity as you.
 
haruspex said:
Just to be accurate about this, what happens after letting go the box is irrelevant to the boy's momentum. The question that needs asking is what horizontal force, if any, caused the box to go from 2m/s to 0m/s as the boy released it.
I think that in this circumstance, we don't need another horizontal force because OP didn't mention about it
 
  • #10
The Vinh said:
I think that in this circumstance, we don't need another horizontal force because OP didn't mention about it
You seem to misunderstand the point that Drakkith and I are making. Yes, we know there is no horizontal force. Our point is that in the absence of a horizontal force the box's velocity cannot change.
 
  • #11
Oh my god, I remembered writing three replies and now two left
 
  • #12
The Vinh said:
Oh my god, I remembered writing three replies and now two left

I had to remove it since it contained the answer to the question. My apologies, I should have put that in the message I sent.
 

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