1. The problem statement, all variables and given/known data Asteroid A is travelling at 40.0m/s and collides with asteroid B which is at rest. Both asteroids have the same mass, but asteroid A deflects off of its path by 30.0° above the horizontal, and asteroid B begins to travel 45.0° below the horizontal. What is the speed of asteroid A? 2. Relevant equations PA1X = PA2X + PB2X PA1X = 40.0m/s*mA PA2X = mA*VA2*cos30° PB2X = mB*VB2*cos45° PA2Y = mA*VA2*sin30° PB2Y = mB*VB2*sin45° 3. The attempt at a solution Equation #1 mB*VB2*sin45° = mA*VA2*sin30° Equation #2 mB*VB2*cos45° + mA*VA2*cos30° = 40.0m/s*mA I isolate mB*VB2 from Equation #1 and get mB*VB2 = (mA*VA2*sin30°)/(sin45). Now I substitute mB*VB2 into Equation #2, and get (cos45°*VA2*sin30°)/(sin45°) + VA2*cos30° = 40.0m/s, I cancelled out mA. Next I isolate VA2*(sin30°)/(tan45°) + cos30° = 40.0m/s Finally VA2 = 78.2679m/s which is impossible because it shouldn't go faster after the collision. Also, my textbook's answer is 23.3m/s.