Momentum question involving vectors

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SUMMARY

The discussion revolves around calculating the impulse required to change a 90.0 kg football player's velocity from 3.6 m/s north to 1.2 m/s northeast. The initial momentum is calculated using the formula p=mv, resulting in 324 kg·m/s north. The correct impulse needed is determined to be 259 N·s at an angle of 17 degrees east of south, contrasting with the incorrect calculation of 410 N·s at 11 degrees east of north. The key to solving this problem lies in vector subtraction to find the difference between the two momentum vectors.

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Homework Statement



What impulse is needed to change the velocity of a 90.0 kg football player from 3.6 m/s towards the north and make it 1.2 m/s toward the northeast? In what direction must the force be exerted?

Homework Equations



p=mv

The Attempt at a Solution



I drew vectors of the two momentums and found the resultant momentum to be 410N.s @ 11 E of N
but the answer in the back of the book is 259N.s 17 E of S
I can't think of any other way to approach this problem...
 
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jumpyroo92 said:

Homework Statement



What impulse is needed to change the velocity of a 90.0 kg football player from 3.6 m/s towards the north and make it 1.2 m/s toward the northeast? In what direction must the force be exerted?

Homework Equations



p=mv

The Attempt at a Solution



I drew vectors of the two momentums and found the resultant momentum to be 410N.s @ 11 E of N
but the answer in the back of the book is 259N.s 17 E of S
I can't think of any other way to approach this problem...
This is a vector subtraction problem. The vector you are trying to find is the difference between the two given vectors.

What momentum vector added to the football player's momentum vector (90kg x 3.6 m/s N) gives the resultant momentum vector (ie. 90kg x 1.2 m/s N45oE)?

AM
 

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