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Momentum to Energy Representation in 3D Box

  1. Mar 18, 2008 #1
    Consider a 3D particle in a square box. One can represent a complete set of quantum states by indexing them with their momentum component quantum numbers. So a state would be |p_x p_y p_z>. If one goes to the energy basis, two momentum states (say |1 0 0> and |0 1 0>) will correspond to the same energy. Does this mean the energy eigenstates are not a complete set due to energy degeneracies? Is there a loss if information here?
  2. jcsd
  3. Mar 18, 2008 #2


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    First, Fouriers theorem says you've got a complete set. There are many situations in which a system has energy degeneracy -- like a gas with identical molecules, or a free fermion particle for which the energy is independent of spin.

    Reilly Atkinson
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