Momentum vectors graph ( from aqa paper)

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SUMMARY

The discussion centers on determining resultant momentum vectors in a collision scenario, specifically using a graphical approach. The user correctly identifies that the resultant vector can be derived by drawing the initial momentum vector and the momentum vector after the collision, both originating from a common point. The angle of collision with the normal, denoted as theta, remains consistent when the object rebounds, confirming that the resultant direction can be established similarly for any resultant vector. The conclusion is that the answer is indeed option B.

PREREQUISITES
  • Understanding of momentum vectors and their graphical representation
  • Knowledge of collision physics, specifically elastic and inelastic collisions
  • Familiarity with vector addition and subtraction techniques
  • Basic trigonometry, particularly relating to angles and triangles
NEXT STEPS
  • Study vector addition techniques in physics
  • Explore the principles of elastic and inelastic collisions
  • Learn about graphical methods for resolving vectors
  • Investigate the role of angles in momentum conservation
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and momentum, as well as educators looking for effective ways to teach vector analysis in collision scenarios.

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Homework Statement
The diagram shows a gas particle about to collide elastically with a wall. box
Which diagram shows the correct change in momentum ∆mv that occurs during the
collision?
https://filestore.aqa.org.uk/sample-papers-and-mark-schemes/2018/june/AQA-74082-QP-JUN18.PDF
question 12 on the multiple choice section
B
Relevant Equations
none
If i were to take one point as my origin and draw the two momentum, one for the initial collestion and one going from the wall after, from the origin point, then drawing horizontally i would get the answer as B as the resultant? Should i assume that for any resultant vector the direction can be found in a similar way ? Just want to make sure my train of thought is correct on this.
the answer is B
 
Physics news on Phys.org
I think your answer is correct. If angle of collision with the normal initially is theta. When it bounces back off, it is also theta. We need to move the initial vector to make it negative and we get diagram B
 

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