How Does Fred the Monkey's Descent Affect the Cylinder's Rotation?

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The discussion centers on calculating the acceleration of Fred the monkey and the tension in the thread as he descends while unwinding it from a rotating steel cylinder. Key equations include the relationship between tension, gravitational force, and the mass of both Fred and the cylinder. Participants emphasize the importance of considering the moment of inertia and angular acceleration of the cylinder in relation to Fred's descent. There is a focus on integrating torque, tension, and gravitational forces to solve the problem accurately. The conversation highlights the need for a comprehensive approach to connect linear and angular motion principles.
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Homework Statement



A 13-kg solid steel cylinder with a 10-cm radius is mounted on bearings so that it rotates freely about a horizontal axis. Around the cylinder is wound a number of turns of a fine gold thread. A 4.0-kg monkey named Fred holds on to the loose end and descends on the unwinding thread as the cylinder turns. Compute Fred's acceleration and the tension in the thread.


Homework Equations


Acceleration: a= Vf-Vo
t
Tension Moving Down: Ft = Fg + ma


The Attempt at a Solution

 
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What, no attempt at a solution? You're also going to need the moment of inertia of the cylinder, I believe
 
Sorry, my attempts at a solution only led me to the fact that Tension=MfG-MfA and then Tension=1/2McA and therefore MfG-MfA=1/2McA. "A" being acceleration, Mf being Mass of Fred, and Mc being mass of the cylinder and G being gravity.
 
Tension=1/2McA

Where did this come from? You should be able to relate the tension to the torque on the cylinder and to its angular acceleration.
 
Don't you have to keep more in mind than just the torque and tension? Such as gravity? I'm not sure how those would fit together.
 
Yes, the last piece of the problem should be relating the angular acceleration of the cylinder to the acceleration of the monkey (and the forces on the monkey)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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