courteous
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Homework Statement
Cylinder with mass of 2 kg can be rotated around fixed horizontal geometrical axis. Around cylinder's circumference there is wounded rope, end of which is pulled by force equal 2,5 N in a horizontal direction, so that cylinder's rotation is accelerated. In what time does end of the rope move for 1,2 m in horizontal direction?
http://img113.imageshack.us/img113/613/cylinder.png
Homework Equations
- m=2kg
- F=2,5N
- x=1,2m
\phi=\omega_0t+\frac{1}{2}\alpha t^2
The Attempt at a Solution
- First and unsuccessful attempt (solution is 1,0s):
\frac{F}{m}=a_{tangential}=r\alpha=r\frac{2\phi}{t^2}=r\frac{2\frac{x}{r}}{t^2}=\frac{2x}{t^2}\Rightarrow t=\sqrt\frac{2mx}{F}=1,4s
- While writing this thread, I gave it another shot, this time including inertia I (and getting, what seems, correct solution):
\frac{2\phi}{t^2}=\alpha=\frac{\tau}{I}=\frac{Fr}{\frac{1}{2}mr^2}=\frac{F}{\frac{1}{2}m\frac{x}{\phi}}=\frac{2F\phi}{mx}\Rightarrow t=\sqrt\frac{mx}{F}=1,0s
What is wrong with first attempt? Ignoring inertia (I) doesn't seem right, but why does (seemingly) rigorous 1. attempt not lead to correct solution (i.e., why is there an extra \sqrt2)?
Yours truly,
courteous.
PS.: Quite likely that I've made grammatical mistakes in 'problem statement'. Please correct me.
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