# Monochromatic Light Through Two Microscope Slides

## Homework Statement

Monochromatic light of wavelength 500nm shines on a pair of identical glass microscope slides that form a very narrow wedge, as shown in the diagram. The top surface of the upper slide and the bottom surface of the lower slide have special coatings on them so that they do not reflect light. The inner surfaces are reflective. The indices of refraction of air and glass are 1.00 and 1.50 respectively. Looking down on the slide from above, you see the fringe pattern shown.
http://img519.imageshack.us/img519/1517/picture2dt0.png [Broken]

## Homework Equations

$$\lambda_{D}$$=$$\frac{2nd}{m-0.5}$$

## The Attempt at a Solution

Since the "P" points to the 4th dark fringe,
m=4
$$\lambda_{D}$$=500nm
n=1 (as the light is traveling the distance "d" in air)
d=?

Isolating for d and solving,
However, the correct answer is 750nm.
If anyone could help me out I'd really appreciate it.

Last edited by a moderator:

Redbelly98
Staff Emeritus
Homework Helper
Your equation disagrees with the case d=0 at the edge of the slides, where we can say n=0 for the dark fringe that appears there.

How would you modify your equation in order to explain the dark fringe at the left edge?

i see.
$$\lambda$$=$$\frac{2nd}{m}$$
if m=0, then d would equal zero

also, setting P as the 3rd dark fringe, you would get the answer 750nm.

however, the equation i stated above happens to be the same equation on my formula sheet as for constructive interference (whereas the dark fringes are obviously destructive).

im assuming for the first dark fringe there is no path length difference, but why does it produce a dark fringe and not a bright spot as my formula predicts?

thank you

Redbelly98
Staff Emeritus